Board: all people visible in the name picker, PIN enters itself, no number before shopping items
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- Name picker wraps in a wider box so five or more people fit
- The board knows each PIN's length and submits when the last digit is typed
- Shopping items typed in are added with no quantity and shown without Mealie's leading 1
- Test updated

Co-Authored-By: Claude Sonnet 5.5 <noreply@anthropic.com>
This commit is contained in:
nmemmertandClaude Sonnet 5.5 committed 2026-10-26 15:12:22 -04:00
1 parent 96b00108bb
commit a45fc1b89c
6 files changed
+13 -12

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@@ -16,7 +16,8 @@ const savePins = () => { fs.mkdirSync(path.dirname(FILE()), { recursive: true })
const hash = (pin, salt) => crypto.scryptSync(String(pin), salt, 32).toString('hex');
const hasPin = uid => !!db()[uid];
const MAX_FAILS = 5, LOCK_MS = 5 * 60e3;
function setPin(uid, pin) { if (!/^\d{4,8}$/.test(String(pin || ''))) throw fail(400, 'A PIN is 4 to 8 digits'); const salt = crypto.randomBytes(12).toString('hex'); db()[uid] = { s: salt, h: hash(pin, salt), fails: 0, until: 0 }; savePins(); }
// (a PIN's length is kept as `n`, so a shared screen can enter it for you as soon as you have typed all the digits)
function setPin(uid, pin) { if (!/^\d{4,8}$/.test(String(pin || ''))) throw fail(400, 'A PIN is 4 to 8 digits'); const salt = crypto.randomBytes(12).toString('hex'); db()[uid] = { s: salt, h: hash(pin, salt), n: String(pin).length, fails: 0, until: 0 }; savePins(); }
function checkPin(uid, pin) {
const r = db()[uid]; if (!r) return false; if (r.until > Date.now()) throw fail(429, 'Too many wrong tries. Wait a few minutes.');
const ok = /^\d{4,8}$/.test(String(pin || '')) && crypto.timingSafeEqual(Buffer.from(hash(pin, r.s), 'hex'), Buffer.from(r.h, 'hex'));
@@ -27,7 +28,7 @@ const ymdOk = s => /^\d{4}-\d{2}-\d{2}$/.test(s || '');
const isKid = u => !!(u.kid && u.kid.on);
const palette = ['#e0742b', '#2f9e6e', '#4f7cff', '#8a5cf0', '#d9453a', '#2aa6a0', '#e5a00d'];
const onBoard = u => !u.disabled && u.board !== false; // the admin picks who is on the family board
const people = () => users.all().filter(onBoard).map((u, i) => ({ id: u.id, name: u.name, kid: isKid(u), pin: hasPin(u.id), color: palette[i % palette.length] }));
const people = () => users.all().filter(onBoard).map((u, i) => ({ id: u.id, name: u.name, kid: isKid(u), pin: hasPin(u.id), pinLen: (db()[u.id] || {}).n || 0, color: palette[i % palette.length] }));
/** Check it is really this person: a child with no PIN just taps their name; everyone else needs their PIN. */
function identify(t, pin, req) {